By possible digit analysis we have the DSs in R4C3, R5C3 and R6C3 as [1,6], [1,6,7] and [1,6,7]. About New York Times Games. 3 Sudoku types . With 5 in R1C1, R7C1 1 by reduction -- R8C1 2 by reduction -- R8C3 6 by reduction -- R8C2 5 by reduction -- R8C5 1 by reduction -- R3C5 5 by reduction -- R9C4 8 by reduction -- R9C2 3 by reduction -- R9C3 9 by reduction -- R7C3 8 by reduction -- R4C3 7 by reduction -- R4C2 8 by reduction. In this game having no success with 1 or 2 by row column scan select digit 3 as promising and get a few easy placements. It a Sudoku hard rich with learning potential. But when you face a Sudoku hard, valid cell by row column scan may be few or non-existent to start with. SuDoku Archive for October 2012. In addition Cycle (1,9) is formed in R9C4, R9C6. A single digit lock is always a valuable asset for hard Sudoku simplification and whenever yoi identify such a possibility, just note it in your mind for future use at the right timer. Identify a second Single digit lock on 5 in R9C5, R9C6 by scan for 5 in R7, C4 -- R9C1 3 by possible digit DS elimination of 5 (because of single digit lock on 5 in R9) from possible digit subset [3,5] in R9C1 (because of [1,4] in C1). Alternately this lock on 6 acts as if 6 actually exists in R8 and that's why a lock on a digit can be used for a scan for the digit. Strategy adopted: start with row column scan coupled with aggressive breakthroughs by advanced Sudoku techniques. Enjoy also learning how to solve Sudoku hard in easy steps. This is a powerful way to get a valid cell. Consider the row column cross-scan: With digit 5 in R4C2, and R7C9, 5 can appear only in two cells R8C3 and R9C3 of bottom left major square Thus the digit 5 is locked in C3 as well as in the parent major square. We can say with 100% certainty that these three digits will be placed in the final solution in only these three cells and nowhere else. Now in addition, a third possible digit subset of [2,6] is formed in R8C3 by DSA reduction of [1,5] from possible digit subset [1,2,5,6] in R8. To solve quickly you need to concentrate. As a ball-park figure, any Sudoku puzzle having number of filled up cells 27 and below should be taken as hard or extremely hard. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. Since the launch of The Crossword in 1942, The Times has captivated solvers by providing engaging word and logic games. The joy of discoveries will then all be yours. Solving a puzzle with a pen is a very different beast than using software that can fill and track pencil marks, highlight all cells with a given candidate and support non destructive cell highlights for chains. Identify the rows and columns with the digit that intersect in a cell in the the 9 square major square. With 7 in R7C6, R1C6 4 by reduction -- R9C6 5 by reduction -- R9C5 1 by reduction -- R9C4 4 by reduction -- R6C5 5 by reduction and exception in C5 -- R1C4 7 by reduction and exception in R1. This Sudoku hard is an especially challenging puzzle rich with Sudoku digit patterns. Instead, the parallel digit scan is carried out on the empty cells of a row or a column. These are rough figures drawn from experience. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. Anyone can read what you share. Try free NYT games like the Mini Crossword, Ken Ken, Sudoku & SET plus our new subscriber-only puzzle Spelling Bee. Step by step solution to the NY Times Sudoku Hard 4th March, 2021 Stage 1: Breakthrough by Single digit lock, Parallel digit scan, DSA and Cycles. Bur that would have been time-taking. Unnecessary enumeration of possible digit subsets in empty cells is avoided to speed up the solution. This leaves the single cell R2C1 for 3 and the byproduct Cycle of (5,6,7) in the other three empty cells of C1. Most important breakthrough at this stage finally has been provided by the single digit lock on 6 in R8C2, R8C3. R6C5 3 by scan for 3 in R4, R5, C4 -- R8C6 3 by scan in R7, C4, C5. Chance of getting a useful pattern from a 5 digit possibility in a cell is remote, and, Such long list of digits CLUTTERS the view and. It is as if the digits Cycle between the cells: if R4C3 1, 6 and 7 can appear in either of the cells R5C3, R6C3. It is a fairly hard Sudoku puzzle. R9C7 4 by reduction of 6 from DS [4,6] from R9 -- R9C8 6 by exception in R9 -- R2C8 4 by exception in C8 -- R2C7 3 by exception in whole game. Reduced DS in two empty cells in C8 is [2,9] -- R2C8 2 by reduction of 9 by R2 -- R2C1 8 by reduction -- R2C7 6 by reduction -- R2C4 3 by exception in R2. Still analyzing this promising neighborhood we detect the possibility of the next breakthrough of R2C1 3 by parallel scan for 3 on empty cells of C1. If by DSA reduction we get a single digit possible for a call, we get a valid cell hit. Observe how the other four empty cells of C6 have been disallowed for 1 by scan for 1 in R2 (disallowing R2C6 for 1), Cycle (1,8) in R6 (disallowing 1 in R6C6), single digit lock in R8 (disallowing R8C6 for 1) and 1 in R9 (disallowing R9C6 for 1). By the way, Sudoku hard solution techniques are included with many of the solutions. Once a few cells are filled in a zone, enumerating the rest gets easier. The elimination of four empty cells for 5 in row R2 is shown by red arrows in the Stage 2 solution figure below. For example, in this case, after you place 8 in R8C7, it will be easy for you to identify a Cycle of (1,4,5,7) in rest four empty cells without specifically evaluating the possible digit subsets in these cells. Chose between Classic, Monster, Kids and Squiggly, and easy, medium, hard and very hard skill levels We "live-solve" the New York Times "Hard" Sudoku on 31 Jan 19. . Short length easy possible digit subsets are evaluated for nearly all empty cells without any easy success. Observe how three empty cells of R8C1, R8C2, R8C3 are disallowed for digit 8 by the presence of digit 8 in the bottom left major square. The Hint button will highlight the next logical square to solve that is empty or incorrect. AFRAID INCOME LAGOON STYLUS AFFECT DUPLEX. This Cycle immediately causes the breakthrough of R9C1 7 by reduction of [1,5] from DS of [1,5,7] in R9C1 because of the property of locking the four digits inside the Cycled cells only. R6C2 2 by reduction of 2 by the Cycle (1,6,7) in left middle major square -- R6C6 9 by reduction -- R3C6 8 by reduction -- R2C4 9 by reduction -- R3C1 7 by reduction -- R8C1 5 by reduction -- R8C2 7 by reduction. With R7C5 9, R5C5 1 by reduction -- R5C4 8 by reduction -- R4C4 2 by reduction -- R6C4 6 by reduction -- R6C5 3 by reduction -- R6C6 9 by reduction -- R8C6 3 by reduction. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. Do you play the New York Times Sudoku? If Costner's 1989 baseball movie had featured zombies, it could have been called - FIELD OF "SCREAMS" (Distributed by Tribune Content Agency) We eliminate repeated digits when considering digits of two or three zones together. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). You can include the QR code to any puzzle that is 9x9, for instance, to make it unique. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). This helps to form a new Cycle (1,5,8) in R3C5, R8C5, R9C5 -- R1C5 6 by reduction. With only 24 filled up cells this New York Times Sudoku hard puzzle is fairly hard. First success by row-column scan: R8C8 4 because of 4 in R7, R9 -- R9C9 2 by scan for 2 in R7, C7. Before going through the solution solve the puzzle first. Because of the Cycle (6,7) in R7, reduced possible digit subset in three empty cells of R7 is [1,4,9] -- breakthrough R7C3 4 by DSA reduction of [1,9] from DS [1,4,9]. Sunday Los Angeles Times crossword Sunday New York Times crossword Sunday Premier crossword SUDOKU. R5C2 5 by exception in C2 -- R6C9 6 by DSA reduction of [1,7] in C9 from DS [1,6,7] in three empty cells of R6 -- R6C4 1 by reduction of 7 from reduced DS [1,7] in R6 -- R6C3 7 by exception in R6 and by reduction. You may perhaps appreciate that, if you have proceeded to form first the possible digit subsets in these four cells and then identified the formation of the Cycle resulting in the valid cell R2C7 8, it would have taken much longer. The New York Times Sudoku Hard, 17th February, 2021 Before going through the solution solve the puzzle first. Description- Self Solving Sudoku- Slice and Dice- Locked Candidates Pointing- Locked Candidates Claiming- Pairs- Locked Candidates Pointing- New York Times S. With this basic concept in place start row column scan for the lowest digit 1 and continue the process till a digit is finished or ends in a block of no more success. Both digits 1 and 8 appear together in column C1 but not in any cell of the left major square. That's why though we start a Sudoku hard solution with systematic row column scan, we also look for other advanced digit patterns for early breakthroughs of valid digits. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). Copyright: Atanu Chaudhuri and respective Authors. With 9 in R4C9, R4C1 8 by reduction of 9 from possible digit subset of [8,9] in C1 -- R5C1 9 by exception in C1. Copyright: Atanu Chaudhuri and respective Authors. Enjoy also learning how to solve Sudoku hard in easy steps. How to solve the Sudoku hard is explained clearly including all the breakthroughs. In easy ones it can be 36 or more. With 5 in C2, C6, C8, C9 and in C3 by single digit lock, digit 5 can be placed in R2 only in the single cell R2C5. It is followed immediately by a second valid cell for 7 in the promising neighborhood of left middle major square: R5C2 7 by scan for 7 in R6. Observe that the two digits [1,8] appear together in R6 and also in C9, but do not appear in the right middle major square. Look for placing any other possible digit by row-column scan. The NY Times Sudoku Hard 4th March 2021 solved step by step quickly and easily by advanced Sudoku techniques with breakthroughs explained adequately. R4C8 1 by reduction of 8 from DS [1,8] -- R5C8 8 by exception in right middle major square. R2C3 3 by row column scan for 3 in R1, R3, C2 -- R6C7 3 by scan for 3 in R4, R5, C9 -- R8C8 3 by scan in C7, C9. This Sudoku hard is a challenging puzzle rich with Sudoku digit patterns. This lock on C9 immediately participates in a row column scan for 3 in R7, lock in R9, 3 in C5 and 3 in C6 to produce unique digit 3 in cell R8C4 -- R8C4 3. No more digits can be placed by this simple method of row-column scan at this point. R4C4 4 by scan for 4 in R5, R6, C6 -- R4C6 5 by exception in R4 -- R5C5 7 by scan for 7 in C4, C6. The . We'll now show you a special valid cell breakthrough by a combination of advanced patterns of single digit lock and parallel scan. Note: For more details, you may click on the section link on "How the parallel digit scan works" above and return by clicking on browser back button. It reduces the possible digit subset DS in right middle major square to [4,5,7,9] -- breakthrough valid cell R6C8 5 by reduction of [4,7,9] (with [4,7] in C8 and 9 in C6) from DS [4.5.7.9] -- followed by R7C8 3 by DSA reduction of [1,5,7] from DS [1,3,5,7] in C8 -- R7C9 7 by reduction of [1,5] from DS [1,5,7]. Take cell R2C5. By the way, Sudoku hard solution techniques are included with many of the solutions. Okay, continuing to identify more possible single digit locks and breakthroughs, with focused intent it doesn't take much to identify a second single digit lock this time on 1 in cells R8C8, R8C9 by scan for 1 in R9, C7. The possible digit subset in the three empty cells is [1,4,8]. Writing long digit sets takes more time and effort. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). This is a breakthrough that otherwise couldn't have been achieved. Solution to New York Times Sudoku hard, 15th February, 2021 explains step by step how to use Sudoku hard techniques to achieve quick breakthroughs. A possible digit subset DS [2,6] already exists in R6C3 as a part of easily formed digit subset in two empty cells of R6. We have detected the possibility of getting a valid cell R2C7 8. This reduces [1,5] from DS [1,5,7] to produce a major breakthrough of R9C1 7. An often asked questions is, "What makes a Sudoku puzzle hard?". DS in both R4C2 and R4C3 [7,8] by reduction of [2,6] in R4 from possible digit subset [2,6,7,8] in left middle major square. R3C8 1 by scan for 1 in R2, C7, C9 R2C1 9 by reduction of [2,6] in R2 from DS [2,6,9] in top left major square -- R2C1 6 by reduction of 2 in C1 -- R3C2 2 by exception in top left major square R4C2 6 by exception in C2. If you get stuck, we're here to help with handy hints, as we are every day. R4C1 8 by reduction of 3 from DS [3,8] in C1 -- R5C1 3 by exception in C1 -- R5C7 8 by exception in R5. R2C8 7 by DSA reduction of 4 in C8 from DS [4,7] -- R2C7 4 by exception in R2 -- R3C8 9 by scan for 9 in C7 -- R3C7 1 by exception in R3 -- R5C7 7 by exception in C7 -- R5C8 1 by exception in R5. R5C5 7 by DSA reduction of [1,5,8] from DS [1,5,7,8] in C5 -- R6C4 4 by DS reduction of [3,8,9] in C4 from DS [3,4,8,9] in R6. Popular sites for tracking the pandemic such the New York Times Covid tracker have become less useful because they rely on PCR testing; most infected people, if they do test, are using antigen . No further challenges left. The New York Times publishes three puzzle challenges every [] R3C2 4 by scan for 4 in R2, C1, C3 -- R3C3 1 by scan for 1 in R2, C1 -- R6C3 8 by reduction -- R6C2 1 by reduction -- R2C3 7 by reduction -- R2C8 6 by reduction -- R2C2 8 by reduction and exception -- R1C8 4 by reduction -- R1C7 5 by reduction -- R1C1 6 by reduction and exception in R1 -- R7C1 7 by reduction -- R3C1 5 by reduction. The other important property of a parallel digit scan is, it will always be associated with a resultant Cycle in rest of the cells after you get the valid cell. About New York Times Games. R1C7 2 by scan for 2 in R2, R3, C8 -- R1C8 6 by scan for 6 in R2, R3. As a subscriber, you have 10 gift articles to give each month. In this process of parallel digit scan, presence of digit 5 in four columns C2, C6, C8 and C9 in parallel affected or lighted up four empty cells of the scanned row R2 and thus made these four cells invalid for placing digit 5. Select a Word Game to learn more: Wordle. Strategy adopted: start with row column scan coupled with aggressive breakthroughs by advanced Sudoku techniques. You can use a pencil to make mistakes and then erase them. You could have identified the formation of this Cycle first to get the breakthrough. Solve New York Times Sudoku hard February 20, 2021 in quick steps. You get a valid cell breakthrough in R2C5 5. Since the launch of The Crossword in 1942, The Times has captivated solvers by providing engaging word and logic games. With 5 in R1C1, R3C2 2 by reduction -- R5C2 6 by reduction -- R6C3 2 by reduction -- R6C4 6 by reduction -- R5C6 1 by reduction -- R5C4 2 by reduction. By the way, Sudoku hard solution techniques are included with many of the solutions. Game status shown below. Next valid cell is R4C6 7 by scan for 7 in R5, R6, C7. R1C6 9 by reduction -- R9C6 1 by reduction -- R9C4 9 by reduction R2C4 6 by DS reduction of [2,5] from DS [2,5,6] in C4 -- R3C4 5 by scan for 5 in R1 -- R1C4 2 by exception in C4. Because of this effect of limiting the digits inside the Cycle, the possible digit subset in the column C3 is reduced to [3,4,7,8,9] and this creates the breakthrough in R3C3 4 by DSA reduction of [3,7,8,9] (with [8,9] in parent top left major square and [3,7] in second parent R3) from DS [3,4,7,8,9] in C3. By the way, Sudoku hard solution techniques are included with many of the solutions. Printable Sudoku New York TimesPrintable Sudoku New York Times - There are many number of ways that to use Printable Sudoku Puzzles. First valid cell by row column scan is for 5: R4C2 5 by scan for 5 in R5, R6. R4C9 9 by parallel scan for 9 on empty cells of C9: 9 in R2 eliminates R2C9 for 9 leaving R5C9 for 9 -- R2C9 5 by reduction -- R4C7 5 by scan for 5 in R5, C8. If you are alert for detecting a parallel scan opportunity, breakthrough would be much quicker. Instead, focus has been to aggressively create a breakthrough at the earliest as well as taking the opportunity of a valid cell by the simplest technique of row column scan. R3C5 6 by DSA reduction of [1,2,5] from possible digit subset DS [1,2,5,6] in empty cells of C5 and hence in R3C5 -- R2C5 2 by DSA reduction of [1,5] from DS [1,2,5] in C5. An easy catch by opportunistic scan for 9: R9C9 9 by scan in R7, R8. To be able to solve a Sudoku puzzle in a short time you should know how to use the pencil to trace the board. R6C1 7 results in R9C2 7 by scan for 7 in C1 -- R9C1 5 by exception in bottom left major square. Then start the process for the next higher digit. For example, R5C5 2 by DSA reduction of [1,5] in the parent top middle major square itself from the possible digit DS of [1,2,5] in C5. R1C3 3 by DS reduction of [1,6] from DS [1,3,6] in R1 -- R1C9 6 by reduction -- R1C1 1 by exception in R1. If we get one, we should get usually a breakthrough in one step or two. With only 23 filled up, cells this New York Times Sudoku hard puzzle is extra-hard. So we'll next start evaluating 2 or 3 digit possible digit subsets DSs in . This breakthrough DS of [6,8] joins with [6,8] in R8C6 to form breakthrough Cycle [6,8] in C6 reducing DS in C6 to [1,2,9] and causing the breakthrough in R6C6 2 by reduction of [1,9] from C6 DS [1,2,9] -- R6C3 4 by reduction of [2,8] -- R6C4 8 by exception in R6 -- R1C2 4 by scan for 4 in R3, C1, C3. Identify Single digit lock on 6 in R7C7, R7C9 by scan for 6 in R8 -- this lock on 6 participates in next valid cell R9C2 6 by scan for 6 in R7 by the lock, 6 in R8 and 6 in C1. R2C2 8 by scan for 8 in R3 -- R3C2 4 by exception in top left major square. An often asked questions is, "What makes a Sudoku puzzle hard?". It is in three zones or areas - row R2, column C5 and 9 cell top-middle major square. R4C7 7 by scan for 7 in C8, C9 -- R3C7 9 by reduction of 8 from DS [8,9] in R3 -- R3C9 8 by exception in R3 -- R7C9 9 by reduction -- R7C8 8 by reduction -- R4C9 4 by reduction of 9 from DS [4,9] in R4 -- R4C8 9 by exception -- R9C9 3 by exception in C9. These are rough figures drawn from experience. Cycle (4,7) in R1C4, R1C6 in top middle major square and in R1 by reduction of [8,9] in R1 from possible digit subset [4,7,8,9] in top middle major square -- R1C3 5 by exception in R1 as the only cell left for 5. This eliminates the cell R6C1 for any of the two digits. An often asked questions is, "What makes a Sudoku puzzle hard?". This creates Cycle (7,8) in R4. In 2014, we introduced The Mini Crossword followed by Spelling Bee, Letter Boxed, Tiles and Vertex. Note: To know more on DSA reduction technique, click on the above internal link and return (after going through it) by clicking on browser back button. Fill as many cells as you can by row-column scan. R7C4 1 by DSA reduction of 9 from DS [1,9] in R7 -- R7C5 9 by exception in R7. Though number of digit 3 is small, we identify first a single digit lock for 3 in R9C7, R9C9 by cross scan for 3 in R7, C8. Cycle (2,6) in two empty cells R6C3, R6C4 and DS [2,6] in R8C3 by DSA reduction of [1,5] from possible digits [1,2,5,6] in R7 -- a breakthrough Cycle (2,6) formed in R6C3, R8C3. Possible digit subset in central middle major square reduced to [1,4,5,7] -- R5C2 5 by DSA reduction of [2,6] in R5 from [2,5,6] possible digit subset in C2. This is a hard Sudoku puzzle that needed multiple breakthroughs by advanced Sudoku techniques. Play the USA TODAY Sudoku Game. If yes, then we have provided all the NY Times Sudoku Answers. These are rough figures drawn from experience. We are only concerned with the most important fact that digit 5 can appear in only these two cells and NOWHERE ELSE IN THE TWO PARENT ZONES. Next identify the advanced technique of Parallel scan for 8 on empty cells of R8: 8 in bottom left major square eliminates R8C1, R8C2, R8C3 for 8 and 8 in C9 eliminates R8C9 for 8 leaving the single cell R8C7 for 8 -- R8C7 8. Hint #2 . After speed of solution, reducing labor being the main objective, we won't enumerate 4 or 5-digit possibilities or enumerate possible digits for ALL the cells. Now do a parallel scan for 1 in empty cells of column C6 to get the valid cell R1C6 1. Turning attention first on promising zone C6 we get the breakthrough DS [6,8] in R5C6 by DSA reduction of [1,2,9] from column C6 DS [1,2,6,8,9]. Starting the solution process, first valid cell success by row column is for 2: R8C7 2 by scan for 2 in R9, C8, C9 -- R7C1 2 by scan for 2 in R8, R9. But by DSA we get the valid cell, R8C2 9 by reduction of [1,5,7] from bottom left major square DS [1,5,7,9] -- R8C3 1 by reduction of [5,7] in R8 from DS [1,5,7] in bottom left major square. As a ball-park figure, any Sudoku puzzle having number of filled up cells 27 and below should be taken as hard or extremely hard. With 6 in R9C5, R8C2 9 by reduction -- R9C2 6 by reduction. Step by step solution to the New York Times Sudoku Hard 20th February, 2021: Stage 1: Breakthroughs by Double digit scan, DSA technique and Cycles First success by row-column scan: R8C8 4 because of 4 in R7, R9 -- R9C9 2 by scan for 2 in R7, C7. This is the quick method of parallel scan for digit 8 on empty cells of the row R8. New York Times Sudoku Hard 17 February, 2021 solved in four stages that explain all breakthroughs and how those are achieved by advanced Sudoku techniques. This single digit lock has been formed by Cross-scan for 6 in R9, C1 and the Cycle (2,6) formed by DSA in R6C3, R8C3. Move around the grid frequently. This makes the digit invalid in any other cell in the row or column in which the digit is locked. For easier lower level Sudoku games this systematic method of row column scan should provide a smooth path to the final solution. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). 3 in bottom left major square eliminates R7C1 for 3 and 3 in R1 and R3, eliminate the other two empty cells R1C1 and R3C1 for 3. An interesting property of a valid cell by parallel digit scan is, there will always be an associated Cycle after you put the valid digit in its identified cell. Most of the time with Hard you have to go beyond Snyder notation just to solve. Digit possibilities for empty cells are enumerated ONLY WHEN NECESSARY. With much of the empty cells filled up with valid digits, short length possible digits are evaluated conveniently in promising zones by possible digit analysis technique. To be precise, this is what happens in the double digit scan for [1,8] together on the empty cells of the left middle major square. How debt-for-climate swaps can help solve low-income countries' fiscal and environmental challenges at the same time Reason is simple: With more number of cells filled up, cell digit possibilities get shorter and getting them easier. With this, two more empty cells R8C7 and R8C9 are left for 8 in R8. With six digits filled in the left middle major square, it is a very promising zone to look for more valid cell hits. Breakthrough R3C3 4 by DSA reduction of [3,7,8,9] from possible digit subset of [3,4,7,8,9] -- R3C7 8 by reduction from DS [4,8] -- R1C7 4 by reduction and exception in top right major square. With 4 in R1C8, R5C8 9 by reduction -- R5C7 4 by reduction -- R3C7 9 by exception in C7 -- R3C8 9 by exception in whole game. It can also be helpful to mark the columns and rows with pencil marks to work through elimination methods. Because of the series of early breakthroughs by advanced digit patterns, the Sudoku hard could be solved rather easily. The online Sudoku NYT puzzle in this game must be solved using logic. For example, in this case, reduction of 7 from DS of R6C2 gives us a valid cell hit as R6C2 2. Because of 8 in central middle major square, R5C6 6 by reduction of 8 -- R8C6 8 by reduction of 6 -- R8C5 6 by reduction of 8. These puzzles are Every such easy fill at this stage is a bonus. Description- Self Solving Sudoku- Locked Candidates Pointing- Triple Subset- Locked Candidates Claiming- Pair- New York Times Sudoku Hard September 14, 2022-. In medium or easy Sudoku puzzles, number of filled up cells will be more. Because of the series of early breakthroughs by advanced digit patterns, the Sudoku hard could be solved rather easily. Abdlomax 3 yr. ago Hint #1: The word contains three vowels (madness isn't it) one of which, in a different word structure, could be a consonant. In this case for example, after you put 5 in R2C5, a Cycle of remaining four digits [4,6,7,8] is formed. Results of the actions taken shown below. Reduction of instances of 6 from all such empty cells is the gain. With 1 in R7C1, R7C7 5 by reduction -- R9C7 1 by reduction -- R9C4 5 by exception in R9 -- R7C4 9 by exception in whole game. Copyright: Atanu Chaudhuri and respective Authors. This NY Times Sudoku puzzle with only 23 filled cells is fairly hard and well-balanced. As a ball-park figure, any Sudoku puzzle having number of filled up cells 27 and below should be taken as hard or extremely hard. No more easy valid digit 3 possible at this point. With 9 in R8C2, R8C9 4 by reduction -- R8C9 4 by reduction -- R9C9 9 by reduction. The New York Times regularly publishes a number-based puzzle game called NYT Sudoku. Target is to get two-digit possibilities first. With 6 in R6C9, R7C9 4 by reduction -- R7C7 6 by reduction and exception in C7. Primarily, with only two cells left for the two digits, a breakthrough Cycle of (1,8) is formed in a single strike and it leaves only the cell R6C1 for digit 4 by exception in left middle major square. Alternately, if R4C3 6, digut [1,7] will appear in eithe of the cells R5C3, R6C3. R2C3 5 by parallel digit scan for 5 on empty cells of C3: 5 in R1 debars R1C3 for 5, 5 in left middle major square debars R4C3, R5C3 for 5 leaving single cell R2C3 for 5 -- R2C5 1 by reduction of [5,8] from DS [1,5,8] in C5 -- R4C5 5 by reduction of 1 -- R4C4 1 by reduction and R1C5 8 by exception in C5. We are not certain at this point which of the two digits will finally occupy which of the two cells, but taking the two cells together, we are certain that digits [1,8] will certainly occupy these two cells and in no other empty cell in parent zones R6 and left middle square. By this parallel scan for 5 on empty cells of row R2, only one cell R2C5 is left placing digit 5. Use Snyder until it fails. This is shown by "5" in the two cells. Instead of scanning the promising empty cells of a major square FOR A SINGLE DIGIT, in a double digit scan, the promising empty cells of the right middle major square are scanned for TWO DIGITS (1,8) TOGETHER -- Cycle (1,8) formed in R4C8, R5C8 in C8 and parent right middle major square. Well not disturb the Cycle of (6,8) for better understanding of what happened at this stage. For full enjoyment, avoid looking into any solution as well as the answer. As a byproduct the leftover two digits [1,8] form a Cycle of (1,8) in R6C2 and R6C3. Never let go of an effective single digit lock. Elimination of four cells of column C6 for digit 1 by parallel scan is shown by blue arrows in Stage 2 solution figure below. [2,6] in two cells of C3 forms a Cycle in which the two digits get locked and thus disallows appearance of 2 and 6 in any other empty cell of C3. These four digits are locked and are self-sufficient in these four cells, each appearing at least twice in these four cells. So the last breakthrough has been R9C1 7 by reduction of [1,5] from DS [1,5,7] because of the Cycle (1,2,5,6) in bottom left major square. Set union is technical, but this we do by common sense and do naturally. That's why for speed, we prefer to identify parallel digit scan possibilities. Description - Self Solving Sudoku - Slice and Dice - Locked Candidates Pointing - Triple Subset - Pair - Locked Candidates Claiming - New York Times Sudoku Hard October 21, 2022 -. Cycle reduces possible digit subset for R7C4, R7C6 to [5,7] and with [7] in C6 we get the breakthrough R7C5 5 by reduction of 7 followed by R7C4 7 by exception. Enjoy solving Sudoku hard. For full enjoyment, avoid looking into any solution as well as the answer. In the process we may get valid cells, but otherwise our lookout is for identifying for a single digit lock by cross scan. R6C9 4 by DSA reduction of [7,9] from DS [4,7,9] -- R6C7 7 by reduction -- R5C9 9 by exception in right middle major square -- R3C9 3 by exception in C9. JUMBLE. I also believe these puzzles printed in newspapers are intended for an audience that has no idea what I just said. And no more for 2. With 6 in R1C5, R1C6 2 by reduction -- R1C1 5 by reduction -- R1C4 8 by reduction. In easy ones it can be 36 or more. Learn more about how to play The New York Times' word games and logic puzzles: Wordle, Spelling Bee, Letterboxed, Tiles, Vertex, and Sudoku. To start with, R4C9 1 by DSA reduction of [4,9] in R4 from reduced DS [1,4,9] in C9 -- R8C8 1 by single digit lock partner reduction of 1 in R8C9. There is no metric or measurement to decide for sure that a Sudoku puzzle is hard, or not so hard. Play the Daily New York Times Crossword puzzle edited by Will Shortz online. We don't bother about other digits appearing in these two cells. Section below explains in a bit of detail the process of enumerating digits possible in a cell. One of the best ways is to personalize them using QR codes. This will result in a series of valid cells and is a major breakthrough. In a single digit lock, a lone digit is locked in two cells in a 9 cell square as well as in a row or column. 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